ID: Q105537
The information in this article applies to:
To determine the number of days between two dates, you can convert dates to serial numbers and subtract one number from the other. The DateValue() function converts a specified date, beginning with December 30, 1899, to a serial number.
WARNING: ANY USE BY YOU OF THE CODE PROVIDED IN THIS ARTICLE IS AT YOUR OWN RISK. Microsoft provides this macro code "as is" without warranty of any kind, either express or implied, including but not limited to the implied warranties of merchantability and/or fitness for a particular purpose.
The following WordBasic sample macro prompts for a date in the mm/dd/yy format, and returns the number of days between the current date and the specified date.
The DateValue() function converts a specified date, beginning with December 30, 1899, to a serial number.
Syntax: DateValue(DateText$)
Examples
x = DateValue("12/30/1899") ' returns 0 or zero
x = DateValue("12/31/1899") ' returns 1
x = DateValue("12/5/1992") ' returns 33943
The Sgn() function is used to determine if the difference between two dates
is a negative(date in the past) or positive(date in the future) number.
Sub MAIN
On Error GoTo ErrHandler
' Prompt for a date.
otherdate$ = InputBox$("Enter a date in the mm/dd/yy format")
' Convert date to serial format.
serialdate = DateValue(otherdate$)
' Get difference between dates.
numdays = serialdate - Today()
' Determine if difference is past or future.
If Sgn(numdays) = 1 Then
MsgBox "The number of days between today and " + otherdate$ + \
" is" + Str$(numdays) + "."
Else
MsgBox "The date " + enddate$ + " was" + Str$(Abs(numdays)) \
+ " days ago."
End If
If Err <> 0 Then MsgBox "Please enter a valid date."
End Sub
Additional query words: w6macroexample calculate difference
Keywords : kbmacroexample winword word6 word7 word95
Version : WINDOWS: 6.0, 6.0a, 6.0c, 7.0, 7.0a
Platform : WINDOWS
Issue type : kbhowto
Last Reviewed: February 13, 1999