INF: Estimating the Initial SQL Server Memory Setting
ID: Q168697
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The information in this article applies to:
-
Microsoft SQL Server version 6.5
SUMMARY
The following equation provides a way to estimate what the initial SQL
Server memory setting should be on a computer that is dedicated solely to
SQL Server.
y=(.95x-22)*512
In the equation above, 'y' is the sp_configure memory setting in 2-KB pages
and 'x' is the amount of RAM on the computer in MB. You can effectively use
this equation on computers that have an amount of RAM ranging from 64 MB to
2 GB. On smaller systems, using a ratio of the values in the table below
will provide a more accurate recommended configuration setting.
MORE INFORMATION
From the Systems Administration for Microsoft SQL Server 6.5 Student
Workbook, the following data is provided for a start in allocating memory
to SQL Server:
Physical RAM
on a computer
dedicated to
SQL Server Memory dedicated to sp_configure 'memory'
(MB) {x} SQL Server (MB) {y} setting (in 2-KB pages)
---------------------------------------------------------------------------
16 5.468 2,800 (minimum, not recommended)
24 8 4,096 (SQL Server 6.5 default)
32 16 8,192
48 28 14,336
64 40 20,480
128 100 51,200
256 216 110,592
512 464 237,568
Using Excel Linear Regression capability, the last four values can be used
to generate slope and intercepts for a best-fit line of the form y = mx+b.
In this case, m = .9462 and b = (-22.09). For this purpose, .95 and (-22)
will suffice, and the equation becomes y = (0.95)*x-22.
Thus, the appropriate SQL Server memory setting in MB is: (0.95)*(the
amount of physical RAM on the computer, in MB) - 22.
Because the SQL Server memory setting is specified in 2-KB pages (for
example, 2,048 bytes) and because 1 MB equals 1,048,576 bytes, the
conversion factor from MB to 2-KB pages is (1,048,576/2,048) = 512
(2-KB pages/MB), the following equation delivers is the result:
The appropriate SQL Server sp_configure memory setting in 2-KB pages is:
(((0.95)*(the amount of physical RAM on the computer, in MB) - 22)*512).
That is, y = (.95x-22)*512
Notes
- This estimation is only for computers dedicated solely to the use of SQL
Server (that is, the computer is not running as a primary or backup
domain controller, nor is it running WINS, DHCP, IIS, file and print
services, or anything else that takes memory other than Windows NT
Server or Workstation and SQL Server). If the computer is running other
services, you can typically size the largest amount of memory that all
of the other services or applications will use (and add some extra) and
increase the '22' number (that is, the intercept/offset/'b') in the
equation by that amount of additional RAM (in MB) that is unavailable.
- The data this is based on is from 64 to 512 MB of RAM. As with all
statistics, you need to be aware of the statistical insignificance when
going outside of the range of the raw dataset. Specifically, when the
amount of available RAM is less than 64, ratio to nearest number in the
table to determine what your value should be.
For example, if your computer had 36 MB of RAM and was dedicated to SQL
Server, you would make the following calculations:
36 is 4 MB greater than 32, and because the gap in the table between
32 and 48 is 16 MB, your 36 MB of RAM should call for a memory
setting of 4/16=.25 of the gap between these to settings. That is,
28 - 16 = 12 and (.25)*12 = 3, so for your 36-MB SQL Server computer
dedicated to the server, a memory setting of 16+3=19 MB is
appropriate. Converting 19 MB to 2-KB pages implies an sp_configure
memory setting of 19*512=9,728.
On computers with more than 512 MB of RAM, this equation often provides
a good benchmark.
- Although this data set was specifically listed for SQL Server 6.5, it
seems to work well for SQL Server 6.0 too.
- With an insufficiently sized NT Paging File, out-of-Virtual Memory
symptoms may be seen. Check the Windows NT Resource Kit for more
information on Virtual Memory.
Additional query words:
prodsql configure calculation formula
Keywords : kbusage SSrvGen
Version : winnt:6.5
Platform : winnt
Issue type : kbhowto
Last Reviewed: April 14, 1999