ID: Q60734
6.00 6.00a 6.00ax 7.00 | 6.00 6.00a | 1.00 1.50 1.51
MS-DOS | OS/2 | WINDOWS
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The information in this article applies to:
- Microsoft C for MS-DOS, versions 6.0, 6.0a, and 6.0ax
- Microsoft C for OS/2, versions 6.0 and 6.0a
- Microsoft C/C++ for MS-DOS, versions 7.0
- Microsoft Visual C++ for Windows, versions 1.0, 1.5, and 1.51
The following warning was added beginning with Microsoft C version 6.0:
C4127: conditional expression is constant
Microsoft C/C++ version 7.0 and later use the following warning:
C4727: conditional expression is constant
This warning is designed to inform you that the controlling expression of
an if statement or while loop evaluates to a constant, so the body of the
loop is ALWAYS executed or NEVER executed.
The warning may appear in certain expressions that don't seem to be constants, but this is because the compiler will generate this warning if ANY subexpression in a larger conditional expression evaluates to a constant.
The warning is strictly informational and does not necessarily indicate any problems in the code.
In the sample code below, warning C4127 is generated by the optimizing compiler supplied with C version 6.0 if the code is compiled at warning level three or four (/W3 or /W4). The quick compiler (/qc) supplied with C version 6.0 does not generate the warning because it does not check for this situation.
The fast compiler, invoked with the /f switch, supplied with C/C++ version 7.0 and Visual C/C++ versions 1.0 and 1.5 does not generate the C4727 warning at any warning level.
The compilers included with Visual C++ 32-bit edition do not generate any warnings either.
The optimizing compiler, invoked with the /f- switch, supplied with C/C++ version 7.0 and Visual C++ for Windows generates the C4727 warning for the sample code below only at warning level three or four. The optimizing compiler supplied with Visual C/C++ versions 1.0 and 1.5, also invoked with the /f- switch, generates the C4727 warning only at warning level four.
The following expression
( hours >= 0 && hours <= 24 )
is NOT a constant because hours could be EITHER in the range 0 (zero) to
24, or out of that range. However, this expression generates warning C4127
because the left subexpression
hours >= 0
ALWAYS evaluates to true since hours is unsigned and an unsigned int
is ALWAYS greater than or equal to zero. The compiler generates the
warning to inform you of this situation.
/* Compile options needed: none
*/
#include <stdio.h>
void main(void)
{
unsigned hours;
scanf ( "%ud", &hours );
if ( hours >= 0 && hours <= 24 )
printf("Hours OK\n");
else
printf("Hours BAD\n");
}
Making a simple change, such as replacing the ">=" with a ">", eliminates
the warning because the left expression can now evaluate to either true or
false (for example, false if hours = 0; true otherwise).
Additional reference words: 7.00 8.00 8.00c 1.00 1.50 1.51 KBCategory: kbtool kbprb KBSubcategory: CLIss Keywords : kb16bitonly
Last Reviewed: July 18, 1997